Description
We throw a ball upwards – This document contains the worked out solutions to the following questions:
We throw a ball upwards. Its height h (in meters), t seconds after its launch is given by the following equation
h(t) = –t2 +50t+1
- Find the initial height of the ball. Round your answer to 4 decimals if needed and show your calculations. Use the correct notation.
- Find at what time the speed of the ball is zero and find the height of the ball at this moment. Round your answer to 4 decimals if needed and show your calculations. Use the correct notation.
- Use the derivative to find the speed of the ball precisely when it will touch the ground after its launch. Round your answer to 4 decimals if needed and show your calculations. Use the correct notation.
- Calculate the speed and the acceleration of the ball 3 seconds after its launch. Round your answer to 4 decimals if needed and show your calculations. Use the correct notation. Here is a preview of the document.
- Interpret the results of c in the context of the problem. You must write an interpretation ….
Solutions
- Find the initial height of the ball. Round your answer to 4 decimals if needed and show your calculations.
a) Initial height of the ball
Initial height is when time t = 0
h(t) = –t2 +50t+1
h = -02 +50 x 0+1 = 1
h = 1 meter
b) Time at which speed of the ball is zero, and height of the ball at this moment. Round your answer to 4 decimals if needed and show your calculations.
Speed s = …..
Solutions: t = 25 seconds, h = 626 meters
Find all worked out (well explained) solutions to the above questions.
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